13403873017345 has 4 divisors (see below), whose sum is σ = 16084647620820. Its totient is φ = 10723098413872.

The previous prime is 13403873017313. The next prime is 13403873017349. The reversal of 13403873017345 is 54371037830431.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 2576535415281 + 10827337602064 = 1605159^2 + 3290492^2 .

It is a cyclic number.

It is not a de Polignac number, because 13403873017345 - 2⁵ = 13403873017313 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13403873017349) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1340387301730 + ... + 1340387301739.

It is an arithmetic number, because the mean of its divisors is an integer number (4021161905205).

Almost surely, 2^{13403873017345} is an apocalyptic number.

It is an amenable number.

13403873017345 is a deficient number, since it is larger than the sum of its proper divisors (2680774603475).

13403873017345 is an equidigital number, since it uses as much as digits as its factorization.

13403873017345 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2680774603474.

The product of its (nonzero) digits is 2540160, while the sum is 49.

The spelling of 13403873017345 in words is "thirteen trillion, four hundred three billion, eight hundred seventy-three million, seventeen thousand, three hundred forty-five".