13404000001 has 16 divisors (see below), whose sum is σ = 15401902464. Its totient is φ = 11426972544.

The previous prime is 13403999963. The next prime is 13404000017. The reversal of 13404000001 is 10000040431.

13404000001 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a cyclic number.

It is not a de Polignac number, because 13404000001 - 2¹⁵ = 13403967233 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13404000301) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1621986 + ... + 1630228.

It is an arithmetic number, because the mean of its divisors is an integer number (962618904).

Almost surely, 2^13404000001 is an apocalyptic number.

It is an amenable number.

13404000001 is a deficient number, since it is larger than the sum of its proper divisors (1997902463).

13404000001 is an equidigital number, since it uses as much as digits as its factorization.

13404000001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9480.

The product of its (nonzero) digits is 48, while the sum is 13.

Adding to 13404000001 its reverse (10000040431), we get a palindrome (23404040432).

The spelling of 13404000001 in words is "thirteen billion, four hundred four million, one", and thus it is an aban number.