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1340402031041 = 5713923458619
BaseRepresentation
bin10011100000010110001…
…011111101100111000001
311202010210220220021122012
4103200112023331213001
5133430120404443131
62503434443222305
7165561261163343
oct23402613754701
94663726807565
101340402031041
11477509003097
12197941b17995
139952654c898
1448c392c9293
1524d00d7252b
hex138162fd9c1

1340402031041 has 4 divisors (see below), whose sum is σ = 1340425546800. Its totient is φ = 1340378515284.

The previous prime is 1340402030999. The next prime is 1340402031103. The reversal of 1340402031041 is 1401302040431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1340402031041 - 210 = 1340402030017 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1340402030998 and 1340402031016.

It is not an unprimeable number, because it can be changed into a prime (1340402031641) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11672171 + ... + 11786448.

It is an arithmetic number, because the mean of its divisors is an integer number (335106386700).

Almost surely, 21340402031041 is an apocalyptic number.

It is an amenable number.

1340402031041 is a deficient number, since it is larger than the sum of its proper divisors (23515759).

1340402031041 is an equidigital number, since it uses as much as digits as its factorization.

1340402031041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 23515758.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 1340402031041 its reverse (1401302040431), we get a palindrome (2741704071472).

The spelling of 1340402031041 in words is "one trillion, three hundred forty billion, four hundred two million, thirty-one thousand, forty-one".

Divisors: 1 57139 23458619 1340402031041