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1340402113 = 7142144843
BaseRepresentation
bin100111111100100…
…1110100111000001
310110102012111000201
41033321032213001
510221120331423
6341001245201
745134141611
oct11771164701
93412174021
101340402113
11628692a46
12314a93801
1318491285b
14ca03aa41
157ca212ad
hex4fe4e9c1

1340402113 has 8 divisors (see below), whose sum is σ = 1362540096. Its totient is φ = 1318354800.

The previous prime is 1340402093. The next prime is 1340402143. The reversal of 1340402113 is 3112040431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1340402113 - 25 = 1340402081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1340402143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7470 + ... + 52312.

It is an arithmetic number, because the mean of its divisors is an integer number (170317512).

Almost surely, 21340402113 is an apocalyptic number.

It is an amenable number.

1340402113 is a deficient number, since it is larger than the sum of its proper divisors (22137983).

1340402113 is an equidigital number, since it uses as much as digits as its factorization.

1340402113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 45335.

The product of its (nonzero) digits is 288, while the sum is 19.

The square root of 1340402113 is about 36611.5024684866. The cubic root of 1340402113 is about 1102.5840387877.

Adding to 1340402113 its reverse (3112040431), we get a palindrome (4452442544).

The spelling of 1340402113 in words is "one billion, three hundred forty million, four hundred two thousand, one hundred thirteen".

Divisors: 1 71 421 29891 44843 3183853 18878903 1340402113