13404051005233 has 4 divisors (see below), whose sum is σ = 15318915434560. Its totient is φ = 11489186575908.

The previous prime is 13404051005221. The next prime is 13404051005251. The reversal of 13404051005233 is 33250015040431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13404051005233 - 2⁵ = 13404051005201 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13404051005195 and 13404051005204.

It is not an unprimeable number, because it can be changed into a prime (13404051005263) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 957432214653 + ... + 957432214666.

It is an arithmetic number, because the mean of its divisors is an integer number (3829728858640).

Almost surely, 2^{13404051005233} is an apocalyptic number.

It is an amenable number.

13404051005233 is a deficient number, since it is larger than the sum of its proper divisors (1914864429327).

13404051005233 is an equidigital number, since it uses as much as digits as its factorization.

13404051005233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1914864429326.

The product of its (nonzero) digits is 21600, while the sum is 31.

Adding to 13404051005233 its reverse (33250015040431), we get a palindrome (46654066045664).

The spelling of 13404051005233 in words is "thirteen trillion, four hundred four billion, fifty-one million, five thousand, two hundred thirty-three".