13404113 has 4 divisors (see below), whose sum is σ = 13411440. Its totient is φ = 13396788.

The previous prime is 13404091. The next prime is 13404133. The reversal of 13404113 is 31140431.

13404113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 13404113 - 2¹⁴ = 13387729 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 13404091 and 13404100.

It is not an unprimeable number, because it can be changed into a prime (13404133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1658 + ... + 5436.

It is an arithmetic number, because the mean of its divisors is an integer number (3352860).

Almost surely, 2^13404113 is an apocalyptic number.

It is an amenable number.

13404113 is a deficient number, since it is larger than the sum of its proper divisors (7327).

13404113 is an equidigital number, since it uses as much as digits as its factorization.

13404113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7326.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 13404113 is about 3661.1627934305. The cubic root of 13404113 is about 237.5450728859.

Adding to 13404113 its reverse (31140431), we get a palindrome (44544544).

The spelling of 13404113 in words is "thirteen million, four hundred four thousand, one hundred thirteen".