1340426539 has 4 divisors (see below), whose sum is σ = 1346280160. Its totient is φ = 1334572920.

The previous prime is 1340426513. The next prime is 1340426543. The reversal of 1340426539 is 9356240431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1340426539 - 2⁷ = 1340426411 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1340426498 and 1340426507.

It is not an unprimeable number, because it can be changed into a prime (1340426579) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2926467 + ... + 2926924.

It is an arithmetic number, because the mean of its divisors is an integer number (336570040).

Almost surely, 2^1340426539 is an apocalyptic number.

1340426539 is a deficient number, since it is larger than the sum of its proper divisors (5853621).

1340426539 is an equidigital number, since it uses as much as digits as its factorization.

1340426539 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5853620.

The product of its (nonzero) digits is 77760, while the sum is 37.

The square root of 1340426539 is about 36611.8360506544. The cubic root of 1340426539 is about 1102.5907361695.

The spelling of 1340426539 in words is "one billion, three hundred forty million, four hundred twenty-six thousand, five hundred thirty-nine".