13404343403 has 4 divisors (see below), whose sum is σ = 14622920088. Its totient is φ = 12185766720.

The previous prime is 13404343391. The next prime is 13404343411. The reversal of 13404343403 is 30434340431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13404343403 is a prime.

It is a super-3 number, since 3×13404343403³ (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13404343423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 609288326 + ... + 609288347.

It is an arithmetic number, because the mean of its divisors is an integer number (3655730022).

Almost surely, 2^13404343403 is an apocalyptic number.

13404343403 is a deficient number, since it is larger than the sum of its proper divisors (1218576685).

13404343403 is a wasteful number, since it uses less digits than its factorization.

13404343403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1218576684.

The product of its (nonzero) digits is 20736, while the sum is 29.

Adding to 13404343403 its reverse (30434340431), we get a palindrome (43838683834).

The spelling of 13404343403 in words is "thirteen billion, four hundred four million, three hundred forty-three thousand, four hundred three".