134044014011 has 4 divisors (see below), whose sum is σ = 134046131232. Its totient is φ = 134041896792.

The previous prime is 134044013953. The next prime is 134044014029. The reversal of 134044014011 is 110410440431.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 110410440431 = 1193 ⋅92548567.

It is a cyclic number.

It is not a de Polignac number, because 134044014011 - 2¹⁰ = 134044012987 is a prime.

It is a super-3 number, since 3×134044014011³ (a number of 34 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (134044014031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 960620 + ... + 1091273.

It is an arithmetic number, because the mean of its divisors is an integer number (33511532808).

Almost surely, 2^134044014011 is an apocalyptic number.

134044014011 is a deficient number, since it is larger than the sum of its proper divisors (2117221).

134044014011 is an equidigital number, since it uses as much as digits as its factorization.

134044014011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2117220.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 134044014011 its reverse (110410440431), we get a palindrome (244454454442).

The spelling of 134044014011 in words is "one hundred thirty-four billion, forty-four million, fourteen thousand, eleven".