Base | Representation |
---|---|
bin | 11110011110100110010000… |
… | …010011000011100000000001 |
3 | 122120121111010200102211022121 |
4 | 132132212100103003200001 |
5 | 120032134211121130131 |
6 | 1153030553333004241 |
7 | 40143235435204441 |
oct | 3636462023034001 |
9 | 576544120384277 |
10 | 134044055255041 |
11 | 3978a845740a88 |
12 | 1304a776a83681 |
13 | 59a43b962cb69 |
14 | 2515aa44c4121 |
15 | 1076bd8077911 |
hex | 79e9904c3801 |
134044055255041 has 8 divisors (see below), whose sum is σ = 134283509175200. Its totient is φ = 133804795307040.
The previous prime is 134044055255029. The next prime is 134044055255057. The reversal of 134044055255041 is 140552550440431.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-134044055255041 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (134044055255021) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 47109675 + ... + 49873936.
It is an arithmetic number, because the mean of its divisors is an integer number (16785438646900).
Almost surely, 2134044055255041 is an apocalyptic number.
It is an amenable number.
134044055255041 is a deficient number, since it is larger than the sum of its proper divisors (239453920159).
134044055255041 is an equidigital number, since it uses as much as digits as its factorization.
134044055255041 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 96986079.
The product of its (nonzero) digits is 960000, while the sum is 43.
The spelling of 134044055255041 in words is "one hundred thirty-four trillion, forty-four billion, fifty-five million, two hundred fifty-five thousand, forty-one".
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