Base | Representation |
---|---|
bin | 10011100000011000100… |
… | …001000101111001011001 |
3 | 11202010220122110102200220 |
4 | 103200120201011321121 |
5 | 133430210411440231 |
6 | 2503442401150253 |
7 | 165562244364306 |
oct | 23403041057131 |
9 | 4663818412626 |
10 | 1340441124441 |
11 | 477529084591 |
12 | 19795302b389 |
13 | 99531689883 |
14 | 48c405840ad |
15 | 24d044e5896 |
hex | 13818845e59 |
1340441124441 has 8 divisors (see below), whose sum is σ = 1790043064224. Its totient is φ = 892233300480.
The previous prime is 1340441124437. The next prime is 1340441124461. The reversal of 1340441124441 is 1444211440431.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1340441124441 - 22 = 1340441124437 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1340441124461) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 348526711 + ... + 348530556.
It is an arithmetic number, because the mean of its divisors is an integer number (223755383028).
Almost surely, 21340441124441 is an apocalyptic number.
It is an amenable number.
1340441124441 is a deficient number, since it is larger than the sum of its proper divisors (449601939783).
1340441124441 is an equidigital number, since it uses as much as digits as its factorization.
1340441124441 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 697057911.
The product of its (nonzero) digits is 24576, while the sum is 33.
Adding to 1340441124441 its reverse (1444211440431), we get a palindrome (2784652564872).
The spelling of 1340441124441 in words is "one trillion, three hundred forty billion, four hundred forty-one million, one hundred twenty-four thousand, four hundred forty-one".
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