134044123315 has 4 divisors (see below), whose sum is σ = 160852947984. Its totient is φ = 107235298648.

The previous prime is 134044123313. The next prime is 134044123331. The reversal of 134044123315 is 513321440431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 134044123315 - 2¹ = 134044123313 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (134044123313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13404412327 + ... + 13404412336.

It is an arithmetic number, because the mean of its divisors is an integer number (40213236996).

Almost surely, 2^134044123315 is an apocalyptic number.

134044123315 is a deficient number, since it is larger than the sum of its proper divisors (26808824669).

134044123315 is an equidigital number, since it uses as much as digits as its factorization.

134044123315 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26808824668.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 134044123315 its reverse (513321440431), we get a palindrome (647365563746).

The spelling of 134044123315 in words is "one hundred thirty-four billion, forty-four million, one hundred twenty-three thousand, three hundred fifteen".