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1340451044011 = 2803478220137
BaseRepresentation
bin10011100000011001000…
…110111011101010101011
311202010221100010101210101
4103200121012323222223
5133430220431402021
62503443353530231
7165562424610322
oct23403106735253
94663840111711
101340451044011
1147753373a282
12197956413977
1399533750941
1448c41a070b9
1524d05304a91
hex138191bbaab

1340451044011 has 4 divisors (see below), whose sum is σ = 1340929266952. Its totient is φ = 1339972821072.

The previous prime is 1340451043961. The next prime is 1340451044041. The reversal of 1340451044011 is 1104401540431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1340451044011 - 239 = 790695230123 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1340451044041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 239107266 + ... + 239112871.

It is an arithmetic number, because the mean of its divisors is an integer number (335232316738).

Almost surely, 21340451044011 is an apocalyptic number.

1340451044011 is a deficient number, since it is larger than the sum of its proper divisors (478222941).

1340451044011 is an equidigital number, since it uses as much as digits as its factorization.

1340451044011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 478222940.

The product of its (nonzero) digits is 3840, while the sum is 28.

Adding to 1340451044011 its reverse (1104401540431), we get a palindrome (2444852584442).

The spelling of 1340451044011 in words is "one trillion, three hundred forty billion, four hundred fifty-one million, forty-four thousand, eleven".

Divisors: 1 2803 478220137 1340451044011