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13404531433 = 1710121433643
BaseRepresentation
bin11000111101111100…
…01110101011101001
31021121011222202021011
430132332032223221
5204423030001213
610054041343521
7653114431366
oct143676165351
937534882234
1013404531433
115759565957
122721197ba1
13135813ba07
1491238d46d
15536c0d03d
hex31ef8eae9

13404531433 has 16 divisors (see below), whose sum is σ = 14344183296. Its totient is φ = 12481862400.

The previous prime is 13404531401. The next prime is 13404531449. The reversal of 13404531433 is 33413540431.

It is not a de Polignac number, because 13404531433 - 25 = 13404531401 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13404531395 and 13404531404.

It is not an unprimeable number, because it can be changed into a prime (13404511433) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3677710 + ... + 3681352.

It is an arithmetic number, because the mean of its divisors is an integer number (896511456).

Almost surely, 213404531433 is an apocalyptic number.

It is an amenable number.

13404531433 is a deficient number, since it is larger than the sum of its proper divisors (939651863).

13404531433 is a wasteful number, since it uses less digits than its factorization.

13404531433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5904.

The product of its (nonzero) digits is 25920, while the sum is 31.

The spelling of 13404531433 in words is "thirteen billion, four hundred four million, five hundred thirty-one thousand, four hundred thirty-three".

Divisors: 1 17 101 1717 2143 3643 36431 61931 216443 367943 3679531 6255031 7806949 132718133 788501849 13404531433