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1340453423451 = 31393214516603
BaseRepresentation
bin10011100000011001010…
…000000000100101011011
311202010221111121021202210
4103200121100000211123
5133430222034022301
62503443520530203
7165562454050422
oct23403120004533
94663844537683
101340453423451
11477535014a5a
12197957180963
13995340a49ac
1448c420662b9
1524d05624ad6
hex1381940095b

1340453423451 has 8 divisors (see below), whose sum is σ = 1800129298240. Its totient is φ = 887206582152.

The previous prime is 1340453423429. The next prime is 1340453423459. The reversal of 1340453423451 is 1543243540431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1340453423451 - 221 = 1340451326299 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1340453423459) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1607257885 + ... + 1607258718.

It is an arithmetic number, because the mean of its divisors is an integer number (225016162280).

Almost surely, 21340453423451 is an apocalyptic number.

1340453423451 is a deficient number, since it is larger than the sum of its proper divisors (459675874789).

1340453423451 is a wasteful number, since it uses less digits than its factorization.

1340453423451 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3214516745.

The product of its (nonzero) digits is 345600, while the sum is 39.

Adding to 1340453423451 its reverse (1543243540431), we get a palindrome (2883696963882).

The spelling of 1340453423451 in words is "one trillion, three hundred forty billion, four hundred fifty-three million, four hundred twenty-three thousand, four hundred fifty-one".

Divisors: 1 3 139 417 3214516603 9643549809 446817807817 1340453423451