Base | Representation |
---|---|
bin | 11000111110000001… |
… | …00110110001101011 |
3 | 1021121020011101211102 |
4 | 30133000212301223 |
5 | 204423204420121 |
6 | 10054102552015 |
7 | 653122634555 |
oct | 143700466153 |
9 | 37536141742 |
10 | 13405154411 |
11 | 5759950a10 |
12 | 272143860b |
13 | 13582c943c |
14 | 9124b24d5 |
15 | 536cd290b |
hex | 31f026c6b |
13405154411 has 16 divisors (see below), whose sum is σ = 14971418880. Its totient is φ = 11897111520.
The previous prime is 13405154383. The next prime is 13405154429. The reversal of 13405154411 is 11445150431.
13405154411 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 13405154411 - 210 = 13405153387 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13405154431) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1124066 + ... + 1135928.
It is an arithmetic number, because the mean of its divisors is an integer number (935713680).
Almost surely, 213405154411 is an apocalyptic number.
13405154411 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
13405154411 is a deficient number, since it is larger than the sum of its proper divisors (1566264469).
13405154411 is a wasteful number, since it uses less digits than its factorization.
13405154411 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 14306.
The product of its (nonzero) digits is 4800, while the sum is 29.
The spelling of 13405154411 in words is "thirteen billion, four hundred five million, one hundred fifty-four thousand, four hundred eleven".
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