13405425012121 has 4 divisors (see below), whose sum is σ = 13405436979472. Its totient is φ = 13405413044772.

The previous prime is 13405425012029. The next prime is 13405425012157. The reversal of 13405425012121 is 12121052450431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13405425012121 - 2²³ = 13405416623513 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13405425013121) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4107291 + ... + 6609136.

It is an arithmetic number, because the mean of its divisors is an integer number (3351359244868).

Almost surely, 2^{13405425012121} is an apocalyptic number.

It is an amenable number.

13405425012121 is a deficient number, since it is larger than the sum of its proper divisors (11967351).

13405425012121 is a wasteful number, since it uses less digits than its factorization.

13405425012121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11967350.

The product of its (nonzero) digits is 9600, while the sum is 31.

Adding to 13405425012121 its reverse (12121052450431), we get a palindrome (25526477462552).

The spelling of 13405425012121 in words is "thirteen trillion, four hundred five billion, four hundred twenty-five million, twelve thousand, one hundred twenty-one".