13405433053011 has 4 divisors (see below), whose sum is σ = 17873910737352. Its totient is φ = 8936955368672.

The previous prime is 13405433053003. The next prime is 13405433053081. The reversal of 13405433053011 is 11035033450431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13405433053011 - 2³ = 13405433053003 is a prime.

It is a super-2 number, since 2×13405433053011² (a number of 27 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (13405433053081) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2234238842166 + ... + 2234238842171.

It is an arithmetic number, because the mean of its divisors is an integer number (4468477684338).

Almost surely, 2^{13405433053011} is an apocalyptic number.

13405433053011 is a deficient number, since it is larger than the sum of its proper divisors (4468477684341).

13405433053011 is an equidigital number, since it uses as much as digits as its factorization.

13405433053011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4468477684340.

The product of its (nonzero) digits is 32400, while the sum is 33.

The spelling of 13405433053011 in words is "thirteen trillion, four hundred five billion, four hundred thirty-three million, fifty-three thousand, eleven".