1340655673547 has 8 divisors (see below), whose sum is σ = 1373376794832. Its totient is φ = 1307935609600.

The previous prime is 1340655673543. The next prime is 1340655673597. The reversal of 1340655673547 is 7453765560431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1340655673547 - 2² = 1340655673543 is a prime.

It is a super-2 number, since 2×1340655673547² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1340655673492 and 1340655673501.

It is not an unprimeable number, because it can be changed into a prime (1340655673543) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2704472 + ... + 3161562.

It is an arithmetic number, because the mean of its divisors is an integer number (171672099354).

Almost surely, 2^{1340655673547} is an apocalyptic number.

1340655673547 is a deficient number, since it is larger than the sum of its proper divisors (32721121285).

1340655673547 is an equidigital number, since it uses as much as digits as its factorization.

1340655673547 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 528669.

The product of its (nonzero) digits is 31752000, while the sum is 56.

The spelling of 1340655673547 in words is "one trillion, three hundred forty billion, six hundred fifty-five million, six hundred seventy-three thousand, five hundred forty-seven".