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134081408035 = 5887271911119
BaseRepresentation
bin111110011011111011…
…1111110110000100011
3110211002100211020220101
41330313313332300203
54144044320024120
6141332433523231
712454443110101
oct1746767766043
9424070736811
10134081408035
1151955506423
1221b9b713517
13c84a62a483
1466bd570c71
15374b31990a
hex1f37dfec23

134081408035 has 16 divisors (see below), whose sum is σ = 161152819200. Its totient is φ = 107095157856.

The previous prime is 134081407949. The next prime is 134081408053. The reversal of 134081408035 is 530804180431.

It is a cyclic number.

It is not a de Polignac number, because 134081408035 - 213 = 134081399843 is a prime.

It is a super-2 number, since 2×1340814080352 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 134081407985 and 134081408003.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 12053206 + ... + 12064324.

It is an arithmetic number, because the mean of its divisors is an integer number (10072051200).

Almost surely, 2134081408035 is an apocalyptic number.

134081408035 is a deficient number, since it is larger than the sum of its proper divisors (27071411165).

134081408035 is a wasteful number, since it uses less digits than its factorization.

134081408035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14730.

The product of its (nonzero) digits is 46080, while the sum is 37.

Adding to 134081408035 its reverse (530804180431), we get a palindrome (664885588466).

The spelling of 134081408035 in words is "one hundred thirty-four billion, eighty-one million, four hundred eight thousand, thirty-five".

Divisors: 1 5 887 2719 4435 11119 13595 55595 2411753 9862553 12058765 30232561 49312765 151162805 26816281607 134081408035