1341012011323 has 4 divisors (see below), whose sum is σ = 1341076793320. Its totient is φ = 1340947229328.

The previous prime is 1341012011299. The next prime is 1341012011351. The reversal of 1341012011323 is 3231102101431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1341012011323 - 2¹³ = 1341012003131 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1341012011294 and 1341012011303.

It is not an unprimeable number, because it can be changed into a prime (1341012111323) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32359938 + ... + 32401351.

It is an arithmetic number, because the mean of its divisors is an integer number (335269198330).

Almost surely, 2^{1341012011323} is an apocalyptic number.

1341012011323 is a deficient number, since it is larger than the sum of its proper divisors (64781997).

1341012011323 is an equidigital number, since it uses as much as digits as its factorization.

1341012011323 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 64781996.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 1341012011323 its reverse (3231102101431), we get a palindrome (4572114112754).

The spelling of 1341012011323 in words is "one trillion, three hundred forty-one billion, twelve million, eleven thousand, three hundred twenty-three".