Search a number
-
+
13410304241 = 16780301223
BaseRepresentation
bin11000111110101000…
…10000000011110001
31021121120212001001212
430133110100003301
5204431014213431
610054405205505
7653214463625
oct143724200361
937546761055
1013410304241
115761849074
122723100895
1313593b0489
14913053185
1553749d72b
hex31f5100f1

13410304241 has 4 divisors (see below), whose sum is σ = 13490605632. Its totient is φ = 13330002852.

The previous prime is 13410304211. The next prime is 13410304249. The reversal of 13410304241 is 14240301431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14240301431 = 19749489549.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13410304241 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13410304249) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40150445 + ... + 40150778.

It is an arithmetic number, because the mean of its divisors is an integer number (3372651408).

Almost surely, 213410304241 is an apocalyptic number.

It is an amenable number.

13410304241 is a deficient number, since it is larger than the sum of its proper divisors (80301391).

13410304241 is an equidigital number, since it uses as much as digits as its factorization.

13410304241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 80301390.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 13410304241 its reverse (14240301431), we get a palindrome (27650605672).

The spelling of 13410304241 in words is "thirteen billion, four hundred ten million, three hundred four thousand, two hundred forty-one".

Divisors: 1 167 80301223 13410304241