Base | Representation |
---|---|
bin | 1100001100100110000000… |
… | …0110100001100110100001 |
3 | 1202111000211211002102002011 |
4 | 3003021200012201212201 |
5 | 3224204201024040340 |
6 | 44304410532552521 |
7 | 2552606461042543 |
oct | 303114006414641 |
9 | 52430754072064 |
10 | 13410500221345 |
11 | 43003a7844877 |
12 | 1607065482741 |
13 | 7637b2815986 |
14 | 34510095d693 |
15 | 183c87cec0ea |
hex | c32601a19a1 |
13410500221345 has 16 divisors (see below), whose sum is σ = 16892831128320. Its totient is φ = 10200499190464.
The previous prime is 13410500221343. The next prime is 13410500221351. The reversal of 13410500221345 is 54312200501431.
It is a cyclic number.
It is not a de Polignac number, because 13410500221345 - 21 = 13410500221343 is a prime.
It is a super-3 number, since 3×134105002213453 (a number of 40 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (13410500221343) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 349121650 + ... + 349160059.
It is an arithmetic number, because the mean of its divisors is an integer number (1055801945520).
Almost surely, 213410500221345 is an apocalyptic number.
It is an amenable number.
13410500221345 is a deficient number, since it is larger than the sum of its proper divisors (3482330906975).
13410500221345 is a wasteful number, since it uses less digits than its factorization.
13410500221345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 698281904.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 13410500221345 its reverse (54312200501431), we get a palindrome (67722700722776).
The spelling of 13410500221345 in words is "thirteen trillion, four hundred ten billion, five hundred million, two hundred twenty-one thousand, three hundred forty-five".
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