1341055351057 has 4 divisors (see below), whose sum is σ = 1341390033216. Its totient is φ = 1340720668900.

The previous prime is 1341055350991. The next prime is 1341055351081. The reversal of 1341055351057 is 7501535501431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1341055351057 is a prime.

It is a super-2 number, since 2×1341055351057² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1341055358057) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 167335069 + ... + 167343082.

It is an arithmetic number, because the mean of its divisors is an integer number (335347508304).

Almost surely, 2^{1341055351057} is an apocalyptic number.

It is an amenable number.

1341055351057 is a deficient number, since it is larger than the sum of its proper divisors (334682159).

1341055351057 is an equidigital number, since it uses as much as digits as its factorization.

1341055351057 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 334682158.

The product of its (nonzero) digits is 157500, while the sum is 40.

The spelling of 1341055351057 in words is "one trillion, three hundred forty-one billion, fifty-five million, three hundred fifty-one thousand, fifty-seven".