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1341124220003 = 31257283594823
BaseRepresentation
bin10011100001000001001…
…110111001010001100011
311202012200020211021122112
4103201001032321101203
5133433110300020003
62504034242225535
7165615210531461
oct23410116712143
94665606737575
101341124220003
11477849728377
12197b039552ab
139961005a829
1448ca719b831
1524d444793d8
hex138413b9463

1341124220003 has 16 divisors (see below), whose sum is σ = 1394686212096. Its totient is φ = 1288241694720.

The previous prime is 1341124219973. The next prime is 1341124220047. The reversal of 1341124220003 is 3000224211431.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1341124220003 is a prime.

It is a super-2 number, since 2×13411242200032 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1341124220063) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1957250 + ... + 2552072.

It is an arithmetic number, because the mean of its divisors is an integer number (87167888256).

Almost surely, 21341124220003 is an apocalyptic number.

1341124220003 is a deficient number, since it is larger than the sum of its proper divisors (53561992093).

1341124220003 is a wasteful number, since it uses less digits than its factorization.

1341124220003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 595394.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 1341124220003 its reverse (3000224211431), we get a palindrome (4341348431434).

The spelling of 1341124220003 in words is "one trillion, three hundred forty-one billion, one hundred twenty-four million, two hundred twenty thousand, three".

Divisors: 1 31 257 283 7967 8773 72731 594823 2254661 18439513 152869511 168334909 4738954841 5218382179 43262071613 1341124220003