Base | Representation |
---|---|
bin | 10011100001000001110… |
… | …001100111010010111011 |
3 | 11202012200212221200102102 |
4 | 103201001301213102323 |
5 | 133433120112241103 |
6 | 2504035205254015 |
7 | 165615351066251 |
oct | 23410161472273 |
9 | 4665625850372 |
10 | 1341133321403 |
11 | 477853884397 |
12 | 197b06a0430b |
13 | 99611bc6385 |
14 | 48ca848a5d1 |
15 | 24d45175e88 |
hex | 13841c674bb |
1341133321403 has 8 divisors (see below), whose sum is σ = 1359553030080. Its totient is φ = 1322749696320.
The previous prime is 1341133321397. The next prime is 1341133321427. The reversal of 1341133321403 is 3041233311431.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1341133321403 - 234 = 1323953452219 is a prime.
It is a super-5 number, since 5×13411333214035 (a number of 62 digits) contains 55555 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1341133381403) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8946050 + ... + 9094727.
It is an arithmetic number, because the mean of its divisors is an integer number (169944128760).
Almost surely, 21341133321403 is an apocalyptic number.
1341133321403 is a deficient number, since it is larger than the sum of its proper divisors (18419708677).
1341133321403 is an equidigital number, since it uses as much as digits as its factorization.
1341133321403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18041797.
The product of its (nonzero) digits is 7776, while the sum is 29.
Adding to 1341133321403 its reverse (3041233311431), we get a palindrome (4382366632834).
The spelling of 1341133321403 in words is "one trillion, three hundred forty-one billion, one hundred thirty-three million, three hundred twenty-one thousand, four hundred three".
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