Search a number
-
+
13411433 = 71915919
BaseRepresentation
bin110011001010…
…010001101001
3221020101000202
4303022101221
511413131213
61155241545
7221665250
oct63122151
927211022
1013411433
117630232
1245a92b5
132a17579
141ad1797
15129db58
hexcca469

13411433 has 4 divisors (see below), whose sum is σ = 15327360. Its totient is φ = 11495508.

The previous prime is 13411421. The next prime is 13411441. The reversal of 13411433 is 33411431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13411433 - 24 = 13411417 is a prime.

It is a super-2 number, since 2×134114332 = 359733070226978, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13411483) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 957953 + ... + 957966.

It is an arithmetic number, because the mean of its divisors is an integer number (3831840).

Almost surely, 213411433 is an apocalyptic number.

It is an amenable number.

13411433 is a deficient number, since it is larger than the sum of its proper divisors (1915927).

13411433 is an equidigital number, since it uses as much as digits as its factorization.

13411433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1915926.

The product of its digits is 432, while the sum is 20.

The square root of 13411433 is about 3662.1623393837. The cubic root of 13411433 is about 237.5883062205.

Adding to 13411433 its reverse (33411431), we get a palindrome (46822864).

The spelling of 13411433 in words is "thirteen million, four hundred eleven thousand, four hundred thirty-three".

Divisors: 1 7 1915919 13411433