13411532055353 has 4 divisors (see below), whose sum is σ = 13422269872500. Its totient is φ = 13400794238208.

The previous prime is 13411532055263. The next prime is 13411532055413. The reversal of 13411532055353 is 35355023511431.

13411532055353 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 6548138098489 + 6863393956864 = 2558933^2 + 2619808^2 .

It is a cyclic number.

It is not a de Polignac number, because 13411532055353 - 2¹⁰ = 13411532054329 is a prime.

It is a super-2 number, since 2×13411532055353² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13411532055353.

It is not an unprimeable number, because it can be changed into a prime (13411532054353) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5368906700 + ... + 5368909197.

It is an arithmetic number, because the mean of its divisors is an integer number (3355567468125).

Almost surely, 2^{13411532055353} is an apocalyptic number.

It is an amenable number.

13411532055353 is a deficient number, since it is larger than the sum of its proper divisors (10737817147).

13411532055353 is a wasteful number, since it uses less digits than its factorization.

13411532055353 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10737817146.

The product of its (nonzero) digits is 405000, while the sum is 41.

Adding to 13411532055353 its reverse (35355023511431), we get a palindrome (48766555566784).

The spelling of 13411532055353 in words is "thirteen trillion, four hundred eleven billion, five hundred thirty-two million, fifty-five thousand, three hundred fifty-three".