13411544450001 has 4 divisors (see below), whose sum is σ = 17882059266672. Its totient is φ = 8941029633332.

The previous prime is 13411544449993. The next prime is 13411544450093. The reversal of 13411544450001 is 10005444511431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13411544450001 - 2³ = 13411544449993 is a prime.

It is a super-4 number, since 4×13411544450001⁴ (a number of 54 digits) contains 4444 as substring.

It is not an unprimeable number, because it can be changed into a prime (13411542450001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2235257408331 + ... + 2235257408336.

It is an arithmetic number, because the mean of its divisors is an integer number (4470514816668).

Almost surely, 2^{13411544450001} is an apocalyptic number.

It is an amenable number.

13411544450001 is a deficient number, since it is larger than the sum of its proper divisors (4470514816671).

13411544450001 is an equidigital number, since it uses as much as digits as its factorization.

13411544450001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4470514816670.

The product of its (nonzero) digits is 19200, while the sum is 33.

Adding to 13411544450001 its reverse (10005444511431), we get a palindrome (23416988961432).

The spelling of 13411544450001 in words is "thirteen trillion, four hundred eleven billion, five hundred forty-four million, four hundred fifty thousand, one".