Base | Representation |
---|---|
bin | 111110011101000111… |
… | …1100100000001010011 |
3 | 110211012010121001221201 |
4 | 1330322033210001103 |
5 | 4144140003110103 |
6 | 141340413332031 |
7 | 12455434626421 |
oct | 1747217440123 |
9 | 424163531851 |
10 | 134121144403 |
11 | 519759869a4 |
12 | 21bb0a97017 |
13 | c85593100c |
14 | 66c4956111 |
15 | 374ea6851d |
hex | 1f3a3e4053 |
134121144403 has 4 divisors (see below), whose sum is σ = 134144512128. Its totient is φ = 134097776680.
The previous prime is 134121144401. The next prime is 134121144427. The reversal of 134121144403 is 304441121431.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 134121144403 - 21 = 134121144401 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (134121144401) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11675251 + ... + 11686732.
It is an arithmetic number, because the mean of its divisors is an integer number (33536128032).
Almost surely, 2134121144403 is an apocalyptic number.
134121144403 is a deficient number, since it is larger than the sum of its proper divisors (23367725).
134121144403 is an equidigital number, since it uses as much as digits as its factorization.
134121144403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 23367724.
The product of its (nonzero) digits is 4608, while the sum is 28.
Adding to 134121144403 its reverse (304441121431), we get a palindrome (438562265834).
The spelling of 134121144403 in words is "one hundred thirty-four billion, one hundred twenty-one million, one hundred forty-four thousand, four hundred three".
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