134123323554403 has 4 divisors (see below), whose sum is σ = 141182445846760. Its totient is φ = 127064201262048.

The previous prime is 134123323554349. The next prime is 134123323554449. The reversal of 134123323554403 is 304455323321431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 134123323554403 - 2¹³ = 134123323546211 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 134123323554403.

It is not an unprimeable number, because it can be changed into a prime (134123323558403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3529561146150 + ... + 3529561146187.

It is an arithmetic number, because the mean of its divisors is an integer number (35295611461690).

Almost surely, 2^{134123323554403} is an apocalyptic number.

134123323554403 is a deficient number, since it is larger than the sum of its proper divisors (7059122292357).

134123323554403 is an equidigital number, since it uses as much as digits as its factorization.

134123323554403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7059122292356.

The product of its (nonzero) digits is 1555200, while the sum is 43.

Adding to 134123323554403 its reverse (304455323321431), we get a palindrome (438578646875834).

The spelling of 134123323554403 in words is "one hundred thirty-four trillion, one hundred twenty-three billion, three hundred twenty-three million, five hundred fifty-four thousand, four hundred three".