Base | Representation |
---|---|
bin | 11000111110111110… |
… | …00001111110001001 |
3 | 1021121210011121110002 |
4 | 30133133001332021 |
5 | 204432230130441 |
6 | 10054545532345 |
7 | 653250503426 |
oct | 143737017611 |
9 | 37553147402 |
10 | 13413130121 |
11 | 57633a9206 |
12 | 27240440b5 |
13 | 1359b5c7b1 |
14 | 91358ad4d |
15 | 53785ab9b |
hex | 31f7c1f89 |
13413130121 has 4 divisors (see below), whose sum is σ = 13509627600. Its totient is φ = 13316632644.
The previous prime is 13413130117. The next prime is 13413130153. The reversal of 13413130121 is 12103131431.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13413130121 - 22 = 13413130117 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13413130093 and 13413130102.
It is not an unprimeable number, because it can be changed into a prime (13413130111) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 48248531 + ... + 48248808.
It is an arithmetic number, because the mean of its divisors is an integer number (3377406900).
Almost surely, 213413130121 is an apocalyptic number.
It is an amenable number.
13413130121 is a deficient number, since it is larger than the sum of its proper divisors (96497479).
13413130121 is an equidigital number, since it uses as much as digits as its factorization.
13413130121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 96497478.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 13413130121 its reverse (12103131431), we get a palindrome (25516261552).
The spelling of 13413130121 in words is "thirteen billion, four hundred thirteen million, one hundred thirty thousand, one hundred twenty-one".
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