13413203331403 has 4 divisors (see below), whose sum is σ = 13875727584240. Its totient is φ = 12950679078568.

The previous prime is 13413203331379. The next prime is 13413203331413. The reversal of 13413203331403 is 30413330231431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13413203331403 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13413203331413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 231262126375 + ... + 231262126432.

It is an arithmetic number, because the mean of its divisors is an integer number (3468931896060).

Almost surely, 2^{13413203331403} is an apocalyptic number.

13413203331403 is a deficient number, since it is larger than the sum of its proper divisors (462524252837).

13413203331403 is an equidigital number, since it uses as much as digits as its factorization.

13413203331403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 462524252836.

The product of its (nonzero) digits is 23328, while the sum is 31.

Adding to 13413203331403 its reverse (30413330231431), we get a palindrome (43826533562834).

The spelling of 13413203331403 in words is "thirteen trillion, four hundred thirteen billion, two hundred three million, three hundred thirty-one thousand, four hundred three".