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13414013433 = 321978444523
BaseRepresentation
bin11000111111000100…
…11001100111111001
31021121211211111010100
430133202121213321
5204432441412213
610055020510013
7653261142612
oct143742314771
937554744110
1013414013433
115763951917
1227243ab309
13135a0ab872
1491373ac09
15537982773
hex31f8999f9

13414013433 has 12 divisors (see below), whose sum is σ = 20395576240. Its totient is φ = 8472008376.

The previous prime is 13414013407. The next prime is 13414013447. The reversal of 13414013433 is 33431041431.

It is not a de Polignac number, because 13414013433 - 25 = 13414013401 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13414013397 and 13414013406.

It is not an unprimeable number, because it can be changed into a prime (13414013533) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 39222091 + ... + 39222432.

Almost surely, 213414013433 is an apocalyptic number.

It is an amenable number.

13414013433 is a deficient number, since it is larger than the sum of its proper divisors (6981562807).

13414013433 is a wasteful number, since it uses less digits than its factorization.

13414013433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 78444548 (or 78444545 counting only the distinct ones).

The product of its (nonzero) digits is 5184, while the sum is 27.

Adding to 13414013433 its reverse (33431041431), we get a palindrome (46845054864).

The spelling of 13414013433 in words is "thirteen billion, four hundred fourteen million, thirteen thousand, four hundred thirty-three".

Divisors: 1 3 9 19 57 171 78444523 235333569 706000707 1490445937 4471337811 13414013433