Base | Representation |
---|---|
bin | 11000111111000100… |
… | …11001100111111001 |
3 | 1021121211211111010100 |
4 | 30133202121213321 |
5 | 204432441412213 |
6 | 10055020510013 |
7 | 653261142612 |
oct | 143742314771 |
9 | 37554744110 |
10 | 13414013433 |
11 | 5763951917 |
12 | 27243ab309 |
13 | 135a0ab872 |
14 | 91373ac09 |
15 | 537982773 |
hex | 31f8999f9 |
13414013433 has 12 divisors (see below), whose sum is σ = 20395576240. Its totient is φ = 8472008376.
The previous prime is 13414013407. The next prime is 13414013447. The reversal of 13414013433 is 33431041431.
It is not a de Polignac number, because 13414013433 - 25 = 13414013401 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13414013397 and 13414013406.
It is not an unprimeable number, because it can be changed into a prime (13414013533) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 39222091 + ... + 39222432.
Almost surely, 213414013433 is an apocalyptic number.
It is an amenable number.
13414013433 is a deficient number, since it is larger than the sum of its proper divisors (6981562807).
13414013433 is a wasteful number, since it uses less digits than its factorization.
13414013433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 78444548 (or 78444545 counting only the distinct ones).
The product of its (nonzero) digits is 5184, while the sum is 27.
Adding to 13414013433 its reverse (33431041431), we get a palindrome (46845054864).
The spelling of 13414013433 in words is "thirteen billion, four hundred fourteen million, thirteen thousand, four hundred thirty-three".
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