13414836438131 has 4 divisors (see below), whose sum is σ = 13427109848592. Its totient is φ = 13402563027672.

The previous prime is 13414836438127. The next prime is 13414836438173. The reversal of 13414836438131 is 13183463841431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13414836438131 - 2² = 13414836438127 is a prime.

It is a super-2 number, since 2×13414836438131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13414836438131.

It is not an unprimeable number, because it can be changed into a prime (13414836438181) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6136703591 + ... + 6136705776.

It is an arithmetic number, because the mean of its divisors is an integer number (3356777462148).

Almost surely, 2^{13414836438131} is an apocalyptic number.

13414836438131 is a deficient number, since it is larger than the sum of its proper divisors (12273410461).

13414836438131 is a wasteful number, since it uses less digits than its factorization.

13414836438131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12273410460.

The product of its digits is 1990656, while the sum is 50.

The spelling of 13414836438131 in words is "thirteen trillion, four hundred fourteen billion, eight hundred thirty-six million, four hundred thirty-eight thousand, one hundred thirty-one".