Base | Representation |
---|---|
bin | 111110011110001000… |
… | …1111100111110101001 |
3 | 110211021111220122101211 |
4 | 1330330101330332221 |
5 | 4144222230402403 |
6 | 141344034113121 |
7 | 12456331310350 |
oct | 1747421747651 |
9 | 424244818354 |
10 | 134155325353 |
11 | 51993202615 |
12 | 2200041b7a1 |
13 | c85ca3b02a |
14 | 66c92d2997 |
15 | 3752a6b06d |
hex | 1f3c47cfa9 |
134155325353 has 8 divisors (see below), whose sum is σ = 153323615360. Its totient is φ = 114987846240.
The previous prime is 134155325299. The next prime is 134155325377. The reversal of 134155325353 is 353523551431.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 134155325353 - 29 = 134155324841 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (134155325653) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 207013 + ... + 557821.
It is an arithmetic number, because the mean of its divisors is an integer number (19165451920).
Almost surely, 2134155325353 is an apocalyptic number.
It is an amenable number.
134155325353 is a deficient number, since it is larger than the sum of its proper divisors (19168290007).
134155325353 is an equidigital number, since it uses as much as digits as its factorization.
134155325353 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 405447.
The product of its digits is 405000, while the sum is 40.
Adding to 134155325353 its reverse (353523551431), we get a palindrome (487678876784).
The spelling of 134155325353 in words is "one hundred thirty-four billion, one hundred fifty-five million, three hundred twenty-five thousand, three hundred fifty-three".
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