Base | Representation |
---|---|
bin | 10011100001100010001… |
… | …000101001110001011011 |
3 | 11202021002201112101102211 |
4 | 103201202020221301123 |
5 | 133440223103404041 |
6 | 2504205121535551 |
7 | 165634662542311 |
oct | 23414210516133 |
9 | 4667081471384 |
10 | 1341676231771 |
11 | 478002289a47 |
12 | 1980387a45b7 |
13 | 9969a523905 |
14 | 48d1a6120b1 |
15 | 24d77b68481 |
hex | 13862229c5b |
1341676231771 has 4 divisors (see below), whose sum is σ = 1374400042344. Its totient is φ = 1308952421200.
The previous prime is 1341676231729. The next prime is 1341676231801. The reversal of 1341676231771 is 1771326761431.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1341676231771 is a prime.
It is a super-2 number, since 2×13416762317712 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1341676231871) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16361905225 + ... + 16361905306.
It is an arithmetic number, because the mean of its divisors is an integer number (343600010586).
Almost surely, 21341676231771 is an apocalyptic number.
1341676231771 is a deficient number, since it is larger than the sum of its proper divisors (32723810573).
1341676231771 is an equidigital number, since it uses as much as digits as its factorization.
1341676231771 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 32723810572.
The product of its digits is 889056, while the sum is 49.
The spelling of 1341676231771 in words is "one trillion, three hundred forty-one billion, six hundred seventy-six million, two hundred thirty-one thousand, seven hundred seventy-one".
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