Base | Representation |
---|---|
bin | 111110011111011110… |
… | …0100001111010011001 |
3 | 110211101122001102220002 |
4 | 1330332330201322121 |
5 | 4144320202303423 |
6 | 141352312342345 |
7 | 12460413346115 |
oct | 1747674417231 |
9 | 424348042802 |
10 | 134200041113 |
11 | 51a06474196 |
12 | 220133a49b5 |
13 | c869096168 |
14 | 66d1212745 |
15 | 3756950228 |
hex | 1f3ef21e99 |
134200041113 has 4 divisors (see below), whose sum is σ = 134975764068. Its totient is φ = 133424318160.
The previous prime is 134200041097. The next prime is 134200041119. The reversal of 134200041113 is 311140002431.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 111841418329 + 22358622784 = 334427^2 + 149528^2 .
It is a cyclic number.
It is not a de Polignac number, because 134200041113 - 24 = 134200041097 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (134200041119) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 387861218 + ... + 387861563.
It is an arithmetic number, because the mean of its divisors is an integer number (33743941017).
Almost surely, 2134200041113 is an apocalyptic number.
It is an amenable number.
134200041113 is a deficient number, since it is larger than the sum of its proper divisors (775722955).
134200041113 is an equidigital number, since it uses as much as digits as its factorization.
134200041113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 775722954.
The product of its (nonzero) digits is 288, while the sum is 20.
Adding to 134200041113 its reverse (311140002431), we get a palindrome (445340043544).
The spelling of 134200041113 in words is "one hundred thirty-four billion, two hundred million, forty-one thousand, one hundred thirteen".
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