Base | Representation |
---|---|
bin | 111110011111101000… |
… | …0101111111011100011 |
3 | 110211102000000201112102 |
4 | 1330333100233323203 |
5 | 4144323031411121 |
6 | 141353022121015 |
7 | 12460506402641 |
oct | 1747720577343 |
9 | 424360021472 |
10 | 134205341411 |
11 | 51a094643a9 |
12 | 2201512016b |
13 | c86a20082b |
14 | 66d1bd2191 |
15 | 375714a90b |
hex | 1f3f42fee3 |
134205341411 has 4 divisors (see below), whose sum is σ = 134207328552. Its totient is φ = 134203354272.
The previous prime is 134205341401. The next prime is 134205341429. The reversal of 134205341411 is 114143502431.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 114143502431 = 7 ⋅16306214633.
It is a cyclic number.
It is not a de Polignac number, because 134205341411 - 210 = 134205340387 is a prime.
It is a super-2 number, since 2×1342053414112 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (134205341401) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 888566 + ... + 1028571.
It is an arithmetic number, because the mean of its divisors is an integer number (33551832138).
Almost surely, 2134205341411 is an apocalyptic number.
134205341411 is a deficient number, since it is larger than the sum of its proper divisors (1987141).
134205341411 is an equidigital number, since it uses as much as digits as its factorization.
134205341411 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1987140.
The product of its (nonzero) digits is 5760, while the sum is 29.
Adding to 134205341411 its reverse (114143502431), we get a palindrome (248348843842).
The spelling of 134205341411 in words is "one hundred thirty-four billion, two hundred five million, three hundred forty-one thousand, four hundred eleven".
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