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13420934393641 = 59444751152117
BaseRepresentation
bin1100001101001100111000…
…0001101110111100101001
31202112000202222211021121221
43003103032001232330221
53224342033201044031
644313254145302041
72553426160043125
oct303231601567451
952460688737557
1013420934393641
114304871644965
121609097934921
1376478644a818
14345810620585
15184198d6da11
hexc34ce06ef29

13420934393641 has 8 divisors (see below), whose sum is σ = 13651477251840. Its totient is φ = 13190493848688.

The previous prime is 13420934393599. The next prime is 13420934393821. The reversal of 13420934393641 is 14639343902431.

13420934393641 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13420934393641 - 213 = 13420934385449 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13420934333641) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 25313686 + ... + 25838431.

It is an arithmetic number, because the mean of its divisors is an integer number (1706434656480).

Almost surely, 213420934393641 is an apocalyptic number.

It is an amenable number.

13420934393641 is a deficient number, since it is larger than the sum of its proper divisors (230542858199).

13420934393641 is an equidigital number, since it uses as much as digits as its factorization.

13420934393641 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 51156623.

The product of its (nonzero) digits is 5038848, while the sum is 52.

The spelling of 13420934393641 in words is "thirteen trillion, four hundred twenty billion, nine hundred thirty-four million, three hundred ninety-three thousand, six hundred forty-one".

Divisors: 1 59 4447 262373 51152117 3017974903 227473464299 13420934393641