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13421021405523 = 34473673801841
BaseRepresentation
bin1100001101001101001100…
…1101101010000101010011
31202112001000001112221111020
43003103103031222011103
53224342222434434043
644313310534250523
72553431264452104
oct303232315520523
952461001487436
1013421021405523
114304906775206
121609100ab6a43
1376479b494644
1434581bdd03ab
151841a1809e83
hexc34d336a153

13421021405523 has 4 divisors (see below), whose sum is σ = 17894695207368. Its totient is φ = 8947347603680.

The previous prime is 13421021405503. The next prime is 13421021405573. The reversal of 13421021405523 is 32550412012431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13421021405523 - 213 = 13421021397331 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13421021405503) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2236836900918 + ... + 2236836900923.

It is an arithmetic number, because the mean of its divisors is an integer number (4473673801842).

Almost surely, 213421021405523 is an apocalyptic number.

13421021405523 is a deficient number, since it is larger than the sum of its proper divisors (4473673801845).

13421021405523 is an equidigital number, since it uses as much as digits as its factorization.

13421021405523 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4473673801844.

The product of its (nonzero) digits is 28800, while the sum is 33.

Adding to 13421021405523 its reverse (32550412012431), we get a palindrome (45971433417954).

The spelling of 13421021405523 in words is "thirteen trillion, four hundred twenty-one billion, twenty-one million, four hundred five thousand, five hundred twenty-three".

Divisors: 1 3 4473673801841 13421021405523