1342120021041 has 4 divisors (see below), whose sum is σ = 1789493361392. Its totient is φ = 894746680692.

The previous prime is 1342120021031. The next prime is 1342120021049. The reversal of 1342120021041 is 1401200212431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1342120021041 - 2⁵ = 1342120021009 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1342120020999 and 1342120021017.

It is not an unprimeable number, because it can be changed into a prime (1342120021049) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 223686670171 + ... + 223686670176.

It is an arithmetic number, because the mean of its divisors is an integer number (447373340348).

Almost surely, 2^{1342120021041} is an apocalyptic number.

It is an amenable number.

1342120021041 is a deficient number, since it is larger than the sum of its proper divisors (447373340351).

1342120021041 is an equidigital number, since it uses as much as digits as its factorization.

1342120021041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 447373340350.

The product of its (nonzero) digits is 384, while the sum is 21.

Adding to 1342120021041 its reverse (1401200212431), we get a palindrome (2743320233472).

The spelling of 1342120021041 in words is "one trillion, three hundred forty-two billion, one hundred twenty million, twenty-one thousand, forty-one".