Base | Representation |
---|---|
bin | 11000111111111011… |
… | …10110101011011011 |
3 | 1021122100101010102010 |
4 | 30133331312223123 |
5 | 204441312212311 |
6 | 10055435041003 |
7 | 653406256044 |
oct | 143775665333 |
9 | 37570333363 |
10 | 13421210331 |
11 | 5767a17a71 |
12 | 27268a0163 |
13 | 135b72b599 |
14 | 9146918cb |
15 | 538404da6 |
hex | 31ff76adb |
13421210331 has 8 divisors (see below), whose sum is σ = 17915929360. Its totient is φ = 8936982432.
The previous prime is 13421210317. The next prime is 13421210393. The reversal of 13421210331 is 13301212431.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13421210331 - 27 = 13421210203 is a prime.
It is a super-2 number, since 2×134212103312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13421210298 and 13421210307.
It is not an unprimeable number, because it can be changed into a prime (13421210311) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2619796 + ... + 2624913.
It is an arithmetic number, because the mean of its divisors is an integer number (2239491170).
Almost surely, 213421210331 is an apocalyptic number.
13421210331 is a deficient number, since it is larger than the sum of its proper divisors (4494719029).
13421210331 is an equidigital number, since it uses as much as digits as its factorization.
13421210331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5245565.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 13421210331 its reverse (13301212431), we get a palindrome (26722422762).
The spelling of 13421210331 in words is "thirteen billion, four hundred twenty-one million, two hundred ten thousand, three hundred thirty-one".
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