1342141233131 has 4 divisors (see below), whose sum is σ = 1373353819992. Its totient is φ = 1310928646272.

The previous prime is 1342141233113. The next prime is 1342141233143. The reversal of 1342141233131 is 1313321412431.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 1342141233131 - 2³⁸ = 1067263326187 is a prime.

It is a super-3 number, since 3×1342141233131³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1342141233094 and 1342141233103.

It is not an unprimeable number, because it can be changed into a prime (1342141233431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15606293366 + ... + 15606293451.

It is an arithmetic number, because the mean of its divisors is an integer number (343338454998).

Almost surely, 2^{1342141233131} is an apocalyptic number.

1342141233131 is a deficient number, since it is larger than the sum of its proper divisors (31212586861).

1342141233131 is an equidigital number, since it uses as much as digits as its factorization.

1342141233131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 31212586860.

The product of its digits is 5184, while the sum is 29.

Adding to 1342141233131 its reverse (1313321412431), we get a palindrome (2655462645562).

The spelling of 1342141233131 in words is "one trillion, three hundred forty-two billion, one hundred forty-one million, two hundred thirty-three thousand, one hundred thirty-one".