Base | Representation |
---|---|
bin | 1100001101001110101010… |
… | …0011110111101001110001 |
3 | 1202112002000100121022010011 |
4 | 3003103222203313221301 |
5 | 3224344023223313431 |
6 | 44313413445534521 |
7 | 2553444062030632 |
oct | 303235243675161 |
9 | 52462010538104 |
10 | 13421413104241 |
11 | 4304a9789025a |
12 | 16091b0114441 |
13 | 76483168a62c |
14 | 345858033889 |
15 | 1841c5dcdcb1 |
hex | c34ea8f7a71 |
13421413104241 has 4 divisors (see below), whose sum is σ = 13442683173184. Its totient is φ = 13400143035300.
The previous prime is 13421413104217. The next prime is 13421413104247. The reversal of 13421413104241 is 14240131412431.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13421413104241 - 211 = 13421413102193 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13421413104247) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10635033525 + ... + 10635034786.
It is an arithmetic number, because the mean of its divisors is an integer number (3360670793296).
Almost surely, 213421413104241 is an apocalyptic number.
It is an amenable number.
13421413104241 is a deficient number, since it is larger than the sum of its proper divisors (21270068943).
13421413104241 is an equidigital number, since it uses as much as digits as its factorization.
13421413104241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21270068942.
The product of its (nonzero) digits is 9216, while the sum is 31.
Adding to 13421413104241 its reverse (14240131412431), we get a palindrome (27661544516672).
The spelling of 13421413104241 in words is "thirteen trillion, four hundred twenty-one billion, four hundred thirteen million, one hundred four thousand, two hundred forty-one".
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