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13421413104241 = 63121270068311
BaseRepresentation
bin1100001101001110101010…
…0011110111101001110001
31202112002000100121022010011
43003103222203313221301
53224344023223313431
644313413445534521
72553444062030632
oct303235243675161
952462010538104
1013421413104241
114304a9789025a
1216091b0114441
1376483168a62c
14345858033889
151841c5dcdcb1
hexc34ea8f7a71

13421413104241 has 4 divisors (see below), whose sum is σ = 13442683173184. Its totient is φ = 13400143035300.

The previous prime is 13421413104217. The next prime is 13421413104247. The reversal of 13421413104241 is 14240131412431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13421413104241 - 211 = 13421413102193 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13421413104247) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10635033525 + ... + 10635034786.

It is an arithmetic number, because the mean of its divisors is an integer number (3360670793296).

Almost surely, 213421413104241 is an apocalyptic number.

It is an amenable number.

13421413104241 is a deficient number, since it is larger than the sum of its proper divisors (21270068943).

13421413104241 is an equidigital number, since it uses as much as digits as its factorization.

13421413104241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 21270068942.

The product of its (nonzero) digits is 9216, while the sum is 31.

Adding to 13421413104241 its reverse (14240131412431), we get a palindrome (27661544516672).

The spelling of 13421413104241 in words is "thirteen trillion, four hundred twenty-one billion, four hundred thirteen million, one hundred four thousand, two hundred forty-one".

Divisors: 1 631 21270068311 13421413104241