13421421133033 has 4 divisors (see below), whose sum is σ = 13884228758340. Its totient is φ = 12958613507728.

The previous prime is 13421421132989. The next prime is 13421421133061. The reversal of 13421421133033 is 33033112412431.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 9682720453849 + 3738700679184 = 3111707^2 + 1933572^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13421421133033 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13421421132986 and 13421421133004.

It is not an unprimeable number, because it can be changed into a prime (13421421133063) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 231403812610 + ... + 231403812667.

It is an arithmetic number, because the mean of its divisors is an integer number (3471057189585).

Almost surely, 2^{13421421133033} is an apocalyptic number.

It is an amenable number.

13421421133033 is a deficient number, since it is larger than the sum of its proper divisors (462807625307).

13421421133033 is an equidigital number, since it uses as much as digits as its factorization.

13421421133033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 462807625306.

The product of its (nonzero) digits is 15552, while the sum is 31.

Adding to 13421421133033 its reverse (33033112412431), we get a palindrome (46454533545464).

The spelling of 13421421133033 in words is "thirteen trillion, four hundred twenty-one billion, four hundred twenty-one million, one hundred thirty-three thousand, thirty-three".