1342143314401 has 4 divisors (see below), whose sum is σ = 1344811591872. Its totient is φ = 1339475036932.

The previous prime is 1342143314363. The next prime is 1342143314411. The reversal of 1342143314401 is 1044133412431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1342143314401 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1342143314411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1334137981 + ... + 1334138986.

It is an arithmetic number, because the mean of its divisors is an integer number (336202897968).

Almost surely, 2^{1342143314401} is an apocalyptic number.

It is an amenable number.

1342143314401 is a deficient number, since it is larger than the sum of its proper divisors (2668277471).

1342143314401 is an equidigital number, since it uses as much as digits as its factorization.

1342143314401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2668277470.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 1342143314401 its reverse (1044133412431), we get a palindrome (2386276726832).

The spelling of 1342143314401 in words is "one trillion, three hundred forty-two billion, one hundred forty-three million, three hundred fourteen thousand, four hundred one".