Base | Representation |
---|---|
bin | 111110100000010111… |
… | …1001101000011100001 |
3 | 110211110201121201000012 |
4 | 1331000233031003201 |
5 | 4144400401232431 |
6 | 141355304534305 |
7 | 12461230020644 |
oct | 1750057150341 |
9 | 424421551005 |
10 | 134230102241 |
11 | 51a214365a4 |
12 | 22021481395 |
13 | c87238cc01 |
14 | 66d51d9a5b |
15 | 37593dc22b |
hex | 1f40bcd0e1 |
134230102241 has 4 divisors (see below), whose sum is σ = 134260263984. Its totient is φ = 134199940500.
The previous prime is 134230102217. The next prime is 134230102247. The reversal of 134230102241 is 142201032431.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 134230102241 - 210 = 134230101217 is a prime.
It is a super-3 number, since 3×1342301022413 (a number of 34 digits) contains 333 as substring.
It is a Duffinian number.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (134230102247) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15074195 + ... + 15083096.
It is an arithmetic number, because the mean of its divisors is an integer number (33565065996).
Almost surely, 2134230102241 is an apocalyptic number.
It is an amenable number.
134230102241 is a deficient number, since it is larger than the sum of its proper divisors (30161743).
134230102241 is an equidigital number, since it uses as much as digits as its factorization.
134230102241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 30161742.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 134230102241 its reverse (142201032431), we get a palindrome (276431134672).
The spelling of 134230102241 in words is "one hundred thirty-four billion, two hundred thirty million, one hundred two thousand, two hundred forty-one".
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