Base | Representation |
---|---|
bin | 10011100010001111101… |
… | …011110011111001111011 |
3 | 11202100001222111022202222 |
4 | 103202033223303321323 |
5 | 133443304222014120 |
6 | 2504413021114255 |
7 | 165662632215215 |
oct | 23421753637173 |
9 | 4670058438688 |
10 | 1342440423035 |
11 | 478364692178 |
12 | 1982106b898b |
13 | 9978c9498aa |
14 | 48d8dcd95b5 |
15 | 24dbecba525 |
hex | 1388faf3e7b |
1342440423035 has 16 divisors (see below), whose sum is σ = 1615632998400. Its totient is φ = 1070816818656.
The previous prime is 1342440423017. The next prime is 1342440423041. The reversal of 1342440423035 is 5303240442431.
It is a cyclic number.
It is not a de Polignac number, because 1342440423035 - 28 = 1342440422779 is a prime.
It is a super-2 number, since 2×13424404230352 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1342440422986 and 1342440423004.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 14469926 + ... + 14562404.
It is an arithmetic number, because the mean of its divisors is an integer number (100977062400).
Almost surely, 21342440423035 is an apocalyptic number.
1342440423035 is a deficient number, since it is larger than the sum of its proper divisors (273192575365).
1342440423035 is an equidigital number, since it uses as much as digits as its factorization.
1342440423035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 100930.
The product of its (nonzero) digits is 138240, while the sum is 35.
Adding to 1342440423035 its reverse (5303240442431), we get a palindrome (6645680865466).
The spelling of 1342440423035 in words is "one trillion, three hundred forty-two billion, four hundred forty million, four hundred twenty-three thousand, thirty-five".
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