1342441430329 has 4 divisors (see below), whose sum is σ = 1342503364176. Its totient is φ = 1342379496484.

The previous prime is 1342441430311. The next prime is 1342441430333. The reversal of 1342441430329 is 9230341442431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1342441430329 - 2¹¹ = 1342441428281 is a prime.

It is a super-2 number, since 2×1342441430329² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1342441430291 and 1342441430300.

It is not an unprimeable number, because it can be changed into a prime (1342441430359) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30934399 + ... + 30977764.

It is an arithmetic number, because the mean of its divisors is an integer number (335625841044).

Almost surely, 2^{1342441430329} is an apocalyptic number.

It is an amenable number.

1342441430329 is a deficient number, since it is larger than the sum of its proper divisors (61933847).

1342441430329 is an equidigital number, since it uses as much as digits as its factorization.

1342441430329 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 61933846.

The product of its (nonzero) digits is 248832, while the sum is 40.

The spelling of 1342441430329 in words is "one trillion, three hundred forty-two billion, four hundred forty-one million, four hundred thirty thousand, three hundred twenty-nine".